Solution to 2008 Problem 19


From the Wien displacement law,

\begin{align*}\lambda^{\text{max}}_1 T_1 = \lambda^{\text{max}}_2 T_2\end{align*}
T_1 = 6000 \mbox{ K}, T_2 = 300 \mbox{ K}, and \lambda^{\text{max}}_1 = 500 \mbox{ nm}, so
\begin{align*}\lambda^{\text{max}}_2 = 500 \mbox{ nm} \cdot \frac{6000 \mbox{ K}}{300 \mbox{ K}} = \boxed{10000 \mbox{ nm}}\e...
Therefore, answer (A) is correct.


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